If a device has 9 Ω resistance and carries 2 A, what is the power dissipated?

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Multiple Choice

If a device has 9 Ω resistance and carries 2 A, what is the power dissipated?

Explanation:
Power dissipated in a resistor is given by P = I^2 R. With a current of 2 A and a resistance of 9 Ω, that’s P = (2)^2 × 9 = 4 × 9 = 36 W. You can also check with the voltage: V = I R = 2 × 9 = 18 V, and P = V I = 18 × 2 = 36 W. The other numbers wouldn’t match these given values, so 36 W is the correct result.

Power dissipated in a resistor is given by P = I^2 R. With a current of 2 A and a resistance of 9 Ω, that’s P = (2)^2 × 9 = 4 × 9 = 36 W. You can also check with the voltage: V = I R = 2 × 9 = 18 V, and P = V I = 18 × 2 = 36 W. The other numbers wouldn’t match these given values, so 36 W is the correct result.

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